2x+4/2x-2=x+4/2x-4

Solution for 2x+4/2x-2=x+4/2x-4 equation:

2x+4/2x-2=x+4/2x-4

We move all terms to the left:

2x+4/2x-2-(x+4/2x-4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 2x-4)!=0

x∈R


We get rid of parentheses

2x+4/2x-x-4/2x+4-2=0

We multiply all the terms by the denominator


2x*2x-x*2x+4*2x-2*2x+4-4=0

We add all the numbers together, and all the variables

2x*2x-x*2x+4*2x-2*2x=0

Wy multiply elements

4x^2-2x^2+8x-4x=0

We add all the numbers together, and all the variables

2x^2+4x=0

a = 2; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·2·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*2}=\frac{0}{4}
=0
$