2x+4/x-3-x-5/x+3=10x+17/x+3

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Solution for 2x+4/x-3-x-5/x+3=10x+17/x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-x+4/x-(5/x)-3+3 = 10*x+17/x+3 // - 10*x+17/x+3

2*x-x-(10*x)+4/x-(5/x)-(17/x)-3-3+3 = 0

2*x-x-10*x+4/x-5*x^-1-17*x^-1-3-3+3 = 0

-9*x^1-18*x^-1-3*x^0 = 0

(-9*x^2-3*x^1-18*x^0)/(x^1) = 0 // * x^2

x^1*(-9*x^2-3*x^1-18*x^0) = 0

x^1

-9*x^2-3*x-18 = 0

-9*x^2-3*x-18 = 0

DELTA = (-3)^2-(-18*(-9)*4)

DELTA = -639

DELTA < 0

x in { } 

x belongs to the empty set

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