2x+40=0.66666/18x

Solution for 2x+40=0.66666/18x equation:

2x+40=0.66666/18x

We move all terms to the left:

2x+40-(0.66666/18x)=0


Domain of the equation: 18x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+0.66666/18x)+40=0

We get rid of parentheses

2x-0.66666/18x+40=0

We multiply all the terms by the denominator


2x*18x+40*18x-0.66666=0

Wy multiply elements

36x^2+720x-0.66666=0

a = 36; b = 720; c = -0.66666;
Δ = b2-4ac
Δ = 7202-4·36·(-0.66666)
Δ = 518495.99904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(720)-\sqrt{518495.99904}}{2*36}=\frac{-720-\sqrt{518495.99904}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(720)+\sqrt{518495.99904}}{2*36}=\frac{-720+\sqrt{518495.99904}}{72}
$