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2x+4=2/3(3x+9)-8
We move all terms to the left:
2x+4-(2/3(3x+9)-8)=0
Domain of the equation: 3(3x+9)-8)!=0We multiply all the terms by the denominator
x∈R
2x*3(3x+9)+4*3(3x+9)-8)-(2-8)=0
We add all the numbers together, and all the variables
2x*3(3x+9)+4*3(3x+9)-8)-(-6)=0
We add all the numbers together, and all the variables
2x*3(3x+9)+4*3(3x+9)=0
Wy multiply elements
6x^2(3+12x(3=0
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