2x+4=3x-3(x-2)-4

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Solution for 2x+4=3x-3(x-2)-4 equation: 



2x+4=3x-3(x-2)-4

We move all terms to the left:

2x+4-(3x-3(x-2)-4)=0



We calculate terms in parentheses: -(3x-3(x-2)-4), so:

3x-3(x-2)-4

We multiply parentheses

3x-3x+6-4

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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