2x+4x(x-1)=5(X-1)

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Solution for 2x+4x(x-1)=5(X-1) equation: 



2x+4x(x-1)=5(x-1)

We move all terms to the left:

2x+4x(x-1)-(5(x-1))=0

We multiply parentheses

4x^2+2x-4x-(5(x-1))=0



We calculate terms in parentheses: -(5(x-1)), so:

5(x-1)

We multiply parentheses

5x-5

Back to the equation:

-(5x-5)



We add all the numbers together, and all the variables

4x^2-2x-(5x-5)=0

We get rid of parentheses

4x^2-2x-5x+5=0

We add all the numbers together, and all the variables

4x^2-7x+5=0

a = 4; b = -7; c = +5;
Δ = b2-4ac
Δ = -72-4·4·5
Δ = -31
Delta is less than zero, so there is no solution for the equation

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