2x+4x+15=25+3(9+2x)-37

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Solution for 2x+4x+15=25+3(9+2x)-37 equation: 



2x+4x+15=25+3(9+2x)-37

We move all terms to the left:

2x+4x+15-(25+3(9+2x)-37)=0

We add all the numbers together, and all the variables

2x+4x-(25+3(2x+9)-37)+15=0

We add all the numbers together, and all the variables

6x-(25+3(2x+9)-37)+15=0



We calculate terms in parentheses: -(25+3(2x+9)-37), so:

25+3(2x+9)-37

determiningTheFunctionDomain
3(2x+9)+25-37

We add all the numbers together, and all the variables

3(2x+9)-12

We multiply parentheses

6x+27-12

We add all the numbers together, and all the variables

6x+15

Back to the equation:

-(6x+15)



We get rid of parentheses

6x-6x-15+15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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