2x+4y=22;3x+2y=17

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x+3y=14

Solution for 2x+4y=22;3x+2y=17 system of equations: 


  • /| 2*x+4*y-22 = 0| 3*x+2*y-17 = 0
  • We try to solve the equation: 2*x+4*y-22 = 0
  • 2*x+4*y-22 = 0 // - 2*x-22
  • 4*y = -(2*x-22) // : 4
  • y = (-(2*x-22))/4
  • y = (22-(2*x))/4
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*((22-(2*x))/4)+3*x-17 = 0| y = (22-(2*x))/4
  • (2*(22-2*x))/4+3*x-17 = 0
  • 2*x-17+11 = 0
  • 2*x-6 = 0
  • 2*x-6 = 0 // + 6
  • 2*x = 6 // : 2
  • x = 6/2
  • x = 3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (22-(2*x))/4: 
  • y = (22-(2*3))/4
  • y = (22-6)/4
  • y = 16/4
  • y = 4
  • We get a system of equations:
  • /| y = 4| x = 3

 

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