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2x+5(2x-4)=2(6x-10)
We move all terms to the left:
2x+5(2x-4)-(2(6x-10))=0
We multiply parentheses
2x+10x-(2(6x-10))-20=0
We calculate terms in parentheses: -(2(6x-10)), so:We add all the numbers together, and all the variables
2(6x-10)
We multiply parentheses
12x-20
Back to the equation:
-(12x-20)
12x-(12x-20)-20=0
We get rid of parentheses
12x-12x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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