2x+5(7x-3)=9(x-5)

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Solution for 2x+5(7x-3)=9(x-5) equation: 



2x+5(7x-3)=9(x-5)

We move all terms to the left:

2x+5(7x-3)-(9(x-5))=0

We multiply parentheses

2x+35x-(9(x-5))-15=0



We calculate terms in parentheses: -(9(x-5)), so:

9(x-5)

We multiply parentheses

9x-45

Back to the equation:

-(9x-45)



We add all the numbers together, and all the variables

37x-(9x-45)-15=0

We get rid of parentheses

37x-9x+45-15=0

We add all the numbers together, and all the variables

28x+30=0

We move all terms containing x to the left, all other terms to the right

28x=-30

x=-30/28

x=-1+1/14

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