2x+5+3(3x-1)=8(1-7x)

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Solution for 2x+5+3(3x-1)=8(1-7x) equation: 



2x+5+3(3x-1)=8(1-7x)

We move all terms to the left:

2x+5+3(3x-1)-(8(1-7x))=0

We add all the numbers together, and all the variables

2x+3(3x-1)-(8(-7x+1))+5=0

We multiply parentheses

2x+9x-(8(-7x+1))-3+5=0



We calculate terms in parentheses: -(8(-7x+1)), so:

8(-7x+1)

We multiply parentheses

-56x+8

Back to the equation:

-(-56x+8)



We add all the numbers together, and all the variables

11x-(-56x+8)+2=0

We get rid of parentheses

11x+56x-8+2=0

We add all the numbers together, and all the variables

67x-6=0

We move all terms containing x to the left, all other terms to the right

67x=6

x=6/67

x=6/67

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