2x+5-4(2x-7)=3x-3+2(2x+7)

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Solution for 2x+5-4(2x-7)=3x-3+2(2x+7) equation:



2x+5-4(2x-7)=3x-3+2(2x+7)
We move all terms to the left:
2x+5-4(2x-7)-(3x-3+2(2x+7))=0
We multiply parentheses
2x-8x-(3x-3+2(2x+7))+28+5=0
We calculate terms in parentheses: -(3x-3+2(2x+7)), so:
3x-3+2(2x+7)
determiningTheFunctionDomain 3x+2(2x+7)-3
We multiply parentheses
3x+4x+14-3
We add all the numbers together, and all the variables
7x+11
Back to the equation:
-(7x+11)
We add all the numbers together, and all the variables
-6x-(7x+11)+33=0
We get rid of parentheses
-6x-7x-11+33=0
We add all the numbers together, and all the variables
-13x+22=0
We move all terms containing x to the left, all other terms to the right
-13x=-22
x=-22/-13
x=1+9/13

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