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2x+5-4(x+4)=-3(x-3)
We move all terms to the left:
2x+5-4(x+4)-(-3(x-3))=0
We multiply parentheses
2x-4x-(-3(x-3))-16+5=0
We calculate terms in parentheses: -(-3(x-3)), so:We add all the numbers together, and all the variables
-3(x-3)
We multiply parentheses
-3x+9
Back to the equation:
-(-3x+9)
-2x-(-3x+9)-11=0
We get rid of parentheses
-2x+3x-9-11=0
We add all the numbers together, and all the variables
x-20=0
We move all terms containing x to the left, all other terms to the right
x=20
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