2x+5-4=7(x+1)-5

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Solution for 2x+5-4=7(x+1)-5 equation: 



2x+5-4=7(x+1)-5

We move all terms to the left:

2x+5-4-(7(x+1)-5)=0

We add all the numbers together, and all the variables

2x-(7(x+1)-5)+1=0



We calculate terms in parentheses: -(7(x+1)-5), so:

7(x+1)-5

We multiply parentheses

7x+7-5

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We get rid of parentheses

2x-7x-2+1=0

We add all the numbers together, and all the variables

-5x-1=0

We move all terms containing x to the left, all other terms to the right

-5x=1

x=1/-5

x=-1/5

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