2x+5/2x=8

Solution for 2x+5/2x=8 equation:

2x+5/2x=8

We move all terms to the left:

2x+5/2x-(8)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We multiply all the terms by the denominator


2x*2x-8*2x+5=0

Wy multiply elements

4x^2-16x+5=0

a = 4; b = -16; c = +5;
Δ = b2-4ac
Δ = -162-4·4·5
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{11}}{2*4}=\frac{16-4\sqrt{11}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{11}}{2*4}=\frac{16+4\sqrt{11}}{8}
$