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2x+5/3x=30
We move all terms to the left:
2x+5/3x-(30)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
2x*3x-30*3x+5=0
Wy multiply elements
6x^2-90x+5=0
a = 6; b = -90; c = +5;
Δ = b2-4ac
Δ = -902-4·6·5
Δ = 7980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7980}=\sqrt{4*1995}=\sqrt{4}*\sqrt{1995}=2\sqrt{1995}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{1995}}{2*6}=\frac{90-2\sqrt{1995}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{1995}}{2*6}=\frac{90+2\sqrt{1995}}{12} $
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