2x+5/x-5+x+10-x/8=x+10/x-5

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Solution for 2x+5/x-5+x+10-x/8=x+10/x-5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+x-(x/8)+5/x-5+10 = x+10/x-5 // - x+10/x-5

2*x+x-(x/8)-x+5/x-(10/x)-5+5+10 = 0

2*x+x-(x/8)-x+5/x-10*x^-1-5+5+10 = 0

15/8*x^1-5*x^-1+10*x^0 = 0

(15/8*x^2+10*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(15/8*x^2+10*x^1-5*x^0) = 0

x^1

(15/8)*x^2+10*x-5 = 0

(15/8)*x^2+10*x-5 = 0

DELTA = 10^2-(-5*4*(15/8))

DELTA = 275/2

DELTA > 0

x = ((275/2)^(1/2)-10)/(2*(15/8)) or x = (-(275/2)^(1/2)-10)/(2*(15/8))

x = 4/15*((275/2)^(1/2)-10) or x = -4/15*((275/2)^(1/2)+10)

x in { -4/15*((275/2)^(1/2)+10), 4/15*((275/2)^(1/2)-10)} 

x in { -4/15*((275/2)^(1/2)+10), 4/15*((275/2)^(1/2)-10) }

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