2x+53x+42x+53x+4=5

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Solution for 2x+53x+42x+53x+4=5 equation: 



2x+53x+42x+53x+4=5

We move all terms to the left:

2x+53x+42x+53x+4-(5)=0

We add all the numbers together, and all the variables

150x-1=0

We move all terms containing x to the left, all other terms to the right

150x=1

x=1/150

x=1/150

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