2x+5=(3/x)+3

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Solution for 2x+5=(3/x)+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+5 = 3/x+3 // - 3/x+3

2*x-(3/x)-3+5 = 0

2*x-3*x^-1-3+5 = 0

2*x^1-3*x^-1+2*x^0 = 0

(2*x^2+2*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+2*x^1-3*x^0) = 0

x^1

2*x^2+2*x-3 = 0

2*x^2+2*x-3 = 0

DELTA = 2^2-(-3*2*4)

DELTA = 28

DELTA > 0

x = (28^(1/2)-2)/(2*2) or x = (-28^(1/2)-2)/(2*2)

x = (2*7^(1/2)-2)/4 or x = (-2*7^(1/2)-2)/4

x in { (-2*7^(1/2)-2)/4, (2*7^(1/2)-2)/4} 

x in { (-2*7^(1/2)-2)/4, (2*7^(1/2)-2)/4 }

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