2x+5=-4(3/8-x)

Solution for 2x+5=-4(3/8-x) equation:

2x+5=-4(3/8-x)

We move all terms to the left:

2x+5-(-4(3/8-x))=0


Domain of the equation: 8-x))!=0

We move all terms containing x to the left, all other terms to the right

-x))!=-8

x!=-8/1

x!=-8

x∈R


We add all the numbers together, and all the variables

2x-(-4(-1x+3/8))+5=0

We multiply all the terms by the denominator


2x*8))-(-4(-1x+3+5*8))=0

We add all the numbers together, and all the variables

2x*8))-(-4(-1x+43))=0

We add all the numbers together, and all the variables

-1x+2x*8))-(-4(=0

Wy multiply elements

16x^2-1x=0

a = 16; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·16·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*16}=\frac{0}{32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*16}=\frac{2}{32}
=1/16
$