2x+5=-4(x+5)2x+5=4x-206x=-25

Solution for 2x+5=-4(x+5)2x+5=4x-206x=-25 equation:

2x+5=-4(x+5)2x+5=4x-206x=-25

We move all terms to the left:

2x+5-(-4(x+5)2x+5)=0


We calculate terms in parentheses: -(-4(x+5)2x+5), so:

-4(x+5)2x+5

We multiply parentheses

-8x^2-40x+5

Back to the equation:

-(-8x^2-40x+5)


We get rid of parentheses

8x^2+40x+2x-5+5=0

We add all the numbers together, and all the variables

8x^2+42x=0

a = 8; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·8·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*8}=\frac{-84}{16}
=-5+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*8}=\frac{0}{16}
=0
$