2x+5=14+((7/3)x)

Solution for 2x+5=14+((7/3)x) equation:

2x+5=14+((7/3)x)

We move all terms to the left:

2x+5-(14+((7/3)x))=0


Domain of the equation: 3)x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(14+((+7/3)x))+5=0

We multiply all the terms by the denominator


2x*3)x))-(14+((+5*3)x))+7=0

We add all the numbers together, and all the variables

2x*3)x))-(14+(15x))+7=0

We add all the numbers together, and all the variables

2x*3)x))-(14+15x)+7=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$