If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x+5=5(x+1)+-3x
We move all terms to the left:
2x+5-(5(x+1)+-3x)=0
We use the square of the difference formula
2x-(5(x+1)-3x)+5=0
We calculate terms in parentheses: -(5(x+1)-3x), so:We get rid of parentheses
5(x+1)-3x
We add all the numbers together, and all the variables
-3x+5(x+1)
We multiply parentheses
-3x+5x+5
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
2x-2x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
| 275=j(25) | | 56=2a+20 | | 3^(x+5)=3.9^x | | 1x+17=5x-23 | | 4x/3+5/4=10x-2x/2 | | 6-x/4=3 | | 5.9-2x=7.1 | | 6=3-19x | | -3/4m-1/2=2=1/4m | | 21+3p=-6(1-5p) | | 7c-3=c+5 | | 5x+7(x-2)=6x+34 | | 2.14x-12.18=-5.7 | | m^2-2m=143 | | 4x/2+5/4=10x-2x/2 | | 1/x-1+3/x=2/x-1 | | x-37=16 | | u/2+8=16 | | x/5=72.5 | | 3=l/3.3 | | y2-3y=0 | | 4x3+9x-5=0 | | 2x^+1=0 | | 1/3(n-1/3=1/6n | | 3x-3-2x-4=5 | | X+x÷5=18 | | 2n+8n=7+9n | | 4/5z-1/5z+1=3/5z+1 | | 1/(x^2)=0.0002 | | x2−x+4= | | x2−x+4=0 | | 4(x-3)=-(x+50 |