2x+5x-4=8(x+1)-5

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Solution for 2x+5x-4=8(x+1)-5 equation: 



2x+5x-4=8(x+1)-5

We move all terms to the left:

2x+5x-4-(8(x+1)-5)=0

We add all the numbers together, and all the variables

7x-(8(x+1)-5)-4=0



We calculate terms in parentheses: -(8(x+1)-5), so:

8(x+1)-5

We multiply parentheses

8x+8-5

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We get rid of parentheses

7x-8x-3-4=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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