2x+5y=19;x+4y=-4

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2x+y=8
x+3y=14

Solution for 2x+5y=19;x+4y=-4 system of equations: 


  • /| 2*x+5*y-19 = 0| x+4*y+4 = 0
  • We try to solve the equation: 2*x+5*y-19 = 0
  • 2*x+5*y-19 = 0 // - 2*x-19
  • 5*y = -(2*x-19) // : 5
  • y = (-(2*x-19))/5
  • y = (19-(2*x))/5
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*((19-(2*x))/5)+x+4 = 0| y = (19-(2*x))/5
  • (4*(19-2*x))/5+x+4 = 0
  • 4-3/5*x+76/5 = 0
  • 96/5-3/5*x = 0
  • 96/5-3/5*x = 0 // - 96/5
  • -3/5*x = -96/5 // : -3/5
  • x = -96/5/(-3/5)
  • x = 32
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (19-(2*x))/5: 
  • y = (19-(2*32))/5
  • y = (19-64)/5
  • y = -45/5
  • y = -9
  • We get a system of equations:
  • /| y = -9| x = 32

 

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