2x+6(3-7x)-5=9(7x-10)

Solution for 2x+6(3-7x)-5=9(7x-10) equation:

2x+6(3-7x)-5=9(7x-10)

We move all terms to the left:

2x+6(3-7x)-5-(9(7x-10))=0

We add all the numbers together, and all the variables

2x+6(-7x+3)-(9(7x-10))-5=0

We multiply parentheses

2x-42x-(9(7x-10))+18-5=0


We calculate terms in parentheses: -(9(7x-10)), so:

9(7x-10)

We multiply parentheses

63x-90

Back to the equation:

-(63x-90)


We add all the numbers together, and all the variables

-40x-(63x-90)+13=0

We get rid of parentheses

-40x-63x+90+13=0

We add all the numbers together, and all the variables

-103x+103=0

We move all terms containing x to the left, all other terms to the right

-103x=-103

x=-103/-103

x=1