2x+6(3x-12)=48

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Solution for 2x+6(3x-12)=48 equation: 



2x+6(3x-12)=48

We move all terms to the left:

2x+6(3x-12)-(48)=0

We multiply parentheses

2x+18x-72-48=0

We add all the numbers together, and all the variables

20x-120=0

We move all terms containing x to the left, all other terms to the right

20x=120

x=120/20

x=6

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