2x+6(3x-12)=88

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Solution for 2x+6(3x-12)=88 equation: 



2x+6(3x-12)=88

We move all terms to the left:

2x+6(3x-12)-(88)=0

We multiply parentheses

2x+18x-72-88=0

We add all the numbers together, and all the variables

20x-160=0

We move all terms containing x to the left, all other terms to the right

20x=160

x=160/20

x=8

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