2x+6(4x-2)=9-5(2x+3)

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Solution for 2x+6(4x-2)=9-5(2x+3) equation: 



2x+6(4x-2)=9-5(2x+3)

We move all terms to the left:

2x+6(4x-2)-(9-5(2x+3))=0

We multiply parentheses

2x+24x-(9-5(2x+3))-12=0



We calculate terms in parentheses: -(9-5(2x+3)), so:

9-5(2x+3)

determiningTheFunctionDomain
-5(2x+3)+9

We multiply parentheses

-10x-15+9

We add all the numbers together, and all the variables

-10x-6

Back to the equation:

-(-10x-6)



We add all the numbers together, and all the variables

26x-(-10x-6)-12=0

We get rid of parentheses

26x+10x+6-12=0

We add all the numbers together, and all the variables

36x-6=0

We move all terms containing x to the left, all other terms to the right

36x=6

x=6/36

x=1/6

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