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2x+6+x=3(x+3)
We move all terms to the left:
2x+6+x-(3(x+3))=0
We add all the numbers together, and all the variables
3x-(3(x+3))+6=0
We calculate terms in parentheses: -(3(x+3)), so:We get rid of parentheses
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
3x-3x-9+6=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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