2x+6-(5-3x)=(x-4)+(6x-3)

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Solution for 2x+6-(5-3x)=(x-4)+(6x-3) equation: 



2x+6-(5-3x)=(x-4)+(6x-3)

We move all terms to the left:

2x+6-(5-3x)-((x-4)+(6x-3))=0

We add all the numbers together, and all the variables

2x-(-3x+5)-((x-4)+(6x-3))+6=0

We get rid of parentheses

2x+3x-((x-4)+(6x-3))-5+6=0



We calculate terms in parentheses: -((x-4)+(6x-3)), so:

(x-4)+(6x-3)

We get rid of parentheses

x+6x-4-3

We add all the numbers together, and all the variables

7x-7

Back to the equation:

-(7x-7)



We add all the numbers together, and all the variables

5x-(7x-7)+1=0

We get rid of parentheses

5x-7x+7+1=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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