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2x+60=1/2x
We move all terms to the left:
2x+60-(1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+1/2x)+60=0
We get rid of parentheses
2x-1/2x+60=0
We multiply all the terms by the denominator
2x*2x+60*2x-1=0
Wy multiply elements
4x^2+120x-1=0
a = 4; b = 120; c = -1;
Δ = b2-4ac
Δ = 1202-4·4·(-1)
Δ = 14416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14416}=\sqrt{16*901}=\sqrt{16}*\sqrt{901}=4\sqrt{901}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-4\sqrt{901}}{2*4}=\frac{-120-4\sqrt{901}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+4\sqrt{901}}{2*4}=\frac{-120+4\sqrt{901}}{8} $
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