2x+6=(x+3)(x+5)

Solution for 2x+6=(x+3)(x+5) equation:

2x+6=(x+3)(x+5)

We move all terms to the left:

2x+6-((x+3)(x+5))=0

We multiply parentheses ..

-((+x^2+5x+3x+15))+2x+6=0


We calculate terms in parentheses: -((+x^2+5x+3x+15)), so:

(+x^2+5x+3x+15)

We get rid of parentheses

x^2+5x+3x+15

We add all the numbers together, and all the variables

x^2+8x+15

Back to the equation:

-(x^2+8x+15)


We add all the numbers together, and all the variables

2x-(x^2+8x+15)+6=0

We get rid of parentheses

-x^2+2x-8x-15+6=0

We add all the numbers together, and all the variables

-1x^2-6x-9=0

a = -1; b = -6; c = -9;
Δ = b2-4ac
Δ = -62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{-2}=-3$