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2x+6=3-1/5x
We move all terms to the left:
2x+6-(3-1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(-1/5x+3)+6=0
We get rid of parentheses
2x+1/5x-3+6=0
We multiply all the terms by the denominator
2x*5x-3*5x+6*5x+1=0
Wy multiply elements
10x^2-15x+30x+1=0
We add all the numbers together, and all the variables
10x^2+15x+1=0
a = 10; b = 15; c = +1;
Δ = b2-4ac
Δ = 152-4·10·1
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{185}}{2*10}=\frac{-15-\sqrt{185}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{185}}{2*10}=\frac{-15+\sqrt{185}}{20} $
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