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2x+6=6x^2
We move all terms to the left:
2x+6-(6x^2)=0
determiningTheFunctionDomain -6x^2+2x+6=0
a = -6; b = 2; c = +6;
Δ = b2-4ac
Δ = 22-4·(-6)·6
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{37}}{2*-6}=\frac{-2-2\sqrt{37}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{37}}{2*-6}=\frac{-2+2\sqrt{37}}{-12} $
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