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2x+6x+8=9x-2(x-2)
We move all terms to the left:
2x+6x+8-(9x-2(x-2))=0
We add all the numbers together, and all the variables
8x-(9x-2(x-2))+8=0
We calculate terms in parentheses: -(9x-2(x-2)), so:We get rid of parentheses
9x-2(x-2)
We multiply parentheses
9x-2x+4
We add all the numbers together, and all the variables
7x+4
Back to the equation:
-(7x+4)
8x-7x-4+8=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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