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2x+6x-4=2(4x-2)
We move all terms to the left:
2x+6x-4-(2(4x-2))=0
We add all the numbers together, and all the variables
8x-(2(4x-2))-4=0
We calculate terms in parentheses: -(2(4x-2)), so:We get rid of parentheses
2(4x-2)
We multiply parentheses
8x-4
Back to the equation:
-(8x-4)
8x-8x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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