2x+7(3x-5)=16+4x

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Solution for 2x+7(3x-5)=16+4x equation: 



2x+7(3x-5)=16+4x

We move all terms to the left:

2x+7(3x-5)-(16+4x)=0

We add all the numbers together, and all the variables

2x+7(3x-5)-(4x+16)=0

We multiply parentheses

2x+21x-(4x+16)-35=0

We get rid of parentheses

2x+21x-4x-16-35=0

We add all the numbers together, and all the variables

19x-51=0

We move all terms containing x to the left, all other terms to the right

19x=51

x=51/19

x=2+13/19

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