2x+7(x+1)=32(x+1)-25

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Solution for 2x+7(x+1)=32(x+1)-25 equation: 



2x+7(x+1)=32(x+1)-25

We move all terms to the left:

2x+7(x+1)-(32(x+1)-25)=0

We multiply parentheses

2x+7x-(32(x+1)-25)+7=0



We calculate terms in parentheses: -(32(x+1)-25), so:

32(x+1)-25

We multiply parentheses

32x+32-25

We add all the numbers together, and all the variables

32x+7

Back to the equation:

-(32x+7)



We add all the numbers together, and all the variables

9x-(32x+7)+7=0

We get rid of parentheses

9x-32x-7+7=0

We add all the numbers together, and all the variables

-23x=0

x=0/-23

x=0

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