2x+7+x=3(x+1)+4,x

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Solution for 2x+7+x=3(x+1)+4,x equation: 



2x+7+x=3(x+1)+4.x

We move all terms to the left:

2x+7+x-(3(x+1)+4.x)=0

We add all the numbers together, and all the variables

3x-(3(x+1)+4.x)+7=0



We calculate terms in parentheses: -(3(x+1)+4.x), so:

3(x+1)+4.x

We add all the numbers together, and all the variables

4.x+3(x+1)

We multiply parentheses

4.x+3x+3

We add all the numbers together, and all the variables

7x+3

Back to the equation:

-(7x+3)



We get rid of parentheses

3x-7x-3+7=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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