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2x+7-4(4x-2)-(-2x+3)=6-2(6x-3)-8-4(1+3x)
We move all terms to the left:
2x+7-4(4x-2)-(-2x+3)-(6-2(6x-3)-8-4(1+3x))=0
We add all the numbers together, and all the variables
2x-4(4x-2)-(-2x+3)-(6-2(6x-3)-8-4(3x+1))+7=0
We multiply parentheses
2x-16x-(-2x+3)-(6-2(6x-3)-8-4(3x+1))+8+7=0
We get rid of parentheses
2x-16x+2x-(6-2(6x-3)-8-4(3x+1))-3+8+7=0
We calculate terms in parentheses: -(6-2(6x-3)-8-4(3x+1)), so:We add all the numbers together, and all the variables
6-2(6x-3)-8-4(3x+1)
determiningTheFunctionDomain -2(6x-3)-4(3x+1)+6-8
We add all the numbers together, and all the variables
-2(6x-3)-4(3x+1)-2
We multiply parentheses
-12x-12x+6-4-2
We add all the numbers together, and all the variables
-24x
Back to the equation:
-(-24x)
-12x-(-24x)+12=0
We get rid of parentheses
-12x+24x+12=0
We add all the numbers together, and all the variables
12x+12=0
We move all terms containing x to the left, all other terms to the right
12x=-12
x=-12/12
x=-1
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