2x+7=-3/4x-4

Solution for 2x+7=-3/4x-4 equation:

2x+7=-3/4x-4

We move all terms to the left:

2x+7-(-3/4x-4)=0


Domain of the equation: 4x-4)!=0

x∈R


We get rid of parentheses

2x+3/4x+4+7=0

We multiply all the terms by the denominator


2x*4x+4*4x+7*4x+3=0

Wy multiply elements

8x^2+16x+28x+3=0

We add all the numbers together, and all the variables

8x^2+44x+3=0

a = 8; b = 44; c = +3;
Δ = b2-4ac
Δ = 442-4·8·3
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{115}}{2*8}=\frac{-44-4\sqrt{115}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{115}}{2*8}=\frac{-44+4\sqrt{115}}{16}
$