2x+7=3+(x-2)

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Solution for 2x+7=3+(x-2) equation: 



2x+7=3+(x-2)

We move all terms to the left:

2x+7-(3+(x-2))=0



We calculate terms in parentheses: -(3+(x-2)), so:

3+(x-2)

determiningTheFunctionDomain
(x-2)+3

We get rid of parentheses

x-2+3

We add all the numbers together, and all the variables

x+1

Back to the equation:

-(x+1)



We get rid of parentheses

2x-x-1+7=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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