2x+7x=3(6-4x)+3(10x-3)

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Solution for 2x+7x=3(6-4x)+3(10x-3) equation: 



2x+7x=3(6-4x)+3(10x-3)

We move all terms to the left:

2x+7x-(3(6-4x)+3(10x-3))=0

We add all the numbers together, and all the variables

2x+7x-(3(-4x+6)+3(10x-3))=0

We add all the numbers together, and all the variables

9x-(3(-4x+6)+3(10x-3))=0



We calculate terms in parentheses: -(3(-4x+6)+3(10x-3)), so:

3(-4x+6)+3(10x-3)

We multiply parentheses

-12x+30x+18-9

We add all the numbers together, and all the variables

18x+9

Back to the equation:

-(18x+9)



We get rid of parentheses

9x-18x-9=0

We add all the numbers together, and all the variables

-9x-9=0

We move all terms containing x to the left, all other terms to the right

-9x=9

x=9/-9

x=-1

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