2x+8(x-3)=2(x-2)

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Solution for 2x+8(x-3)=2(x-2) equation: 



2x+8(x-3)=2(x-2)

We move all terms to the left:

2x+8(x-3)-(2(x-2))=0

We multiply parentheses

2x+8x-(2(x-2))-24=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

10x-(2x-4)-24=0

We get rid of parentheses

10x-2x+4-24=0

We add all the numbers together, and all the variables

8x-20=0

We move all terms containing x to the left, all other terms to the right

8x=20

x=20/8

x=2+1/2

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