2x+8+2x=3(x-1)+12

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Solution for 2x+8+2x=3(x-1)+12 equation: 



2x+8+2x=3(x-1)+12

We move all terms to the left:

2x+8+2x-(3(x-1)+12)=0

We add all the numbers together, and all the variables

4x-(3(x-1)+12)+8=0



We calculate terms in parentheses: -(3(x-1)+12), so:

3(x-1)+12

We multiply parentheses

3x-3+12

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

4x-3x-9+8=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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