2x+8+x=4(3x-8)+20

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Solution for 2x+8+x=4(3x-8)+20 equation: 



2x+8+x=4(3x-8)+20

We move all terms to the left:

2x+8+x-(4(3x-8)+20)=0

We add all the numbers together, and all the variables

3x-(4(3x-8)+20)+8=0



We calculate terms in parentheses: -(4(3x-8)+20), so:

4(3x-8)+20

We multiply parentheses

12x-32+20

We add all the numbers together, and all the variables

12x-12

Back to the equation:

-(12x-12)



We get rid of parentheses

3x-12x+12+8=0

We add all the numbers together, and all the variables

-9x+20=0

We move all terms containing x to the left, all other terms to the right

-9x=-20

x=-20/-9

x=2+2/9

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