2x+8/x=8

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Solution for 2x+8/x=8 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+8/x = 8 // - 8

2*x+8/x-8 = 0

2*x^1+8*x^-1-8*x^0 = 0

(2*x^2-8*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-8*x^1+8*x^0) = 0

x^1

2*x^2-8*x+8 = 0

2*x^2-8*x+8 = 0

DELTA = (-8)^2-(2*4*8)

DELTA = 0

x = 8/(2*2)

x = 2 or x = 2

x in { 2, 2} 

x in { 2, 2 }

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