2x+8=-4(x+1)+6(x+2)

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Solution for 2x+8=-4(x+1)+6(x+2) equation: 



2x+8=-4(x+1)+6(x+2)

We move all terms to the left:

2x+8-(-4(x+1)+6(x+2))=0



We calculate terms in parentheses: -(-4(x+1)+6(x+2)), so:

-4(x+1)+6(x+2)

We multiply parentheses

-4x+6x-4+12

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

2x-2x-8+8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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