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2x+8=2(x-3)+2
We move all terms to the left:
2x+8-(2(x-3)+2)=0
We calculate terms in parentheses: -(2(x-3)+2), so:We get rid of parentheses
2(x-3)+2
We multiply parentheses
2x-6+2
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-2x+4+8=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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